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3/5x^2-12=9
We move all terms to the left:
3/5x^2-12-(9)=0
Domain of the equation: 5x^2!=0We add all the numbers together, and all the variables
x^2!=0/5
x^2!=√0
x!=0
x∈R
3/5x^2-21=0
We multiply all the terms by the denominator
-21*5x^2+3=0
Wy multiply elements
-105x^2+3=0
a = -105; b = 0; c = +3;
Δ = b2-4ac
Δ = 02-4·(-105)·3
Δ = 1260
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{1260}=\sqrt{36*35}=\sqrt{36}*\sqrt{35}=6\sqrt{35}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-6\sqrt{35}}{2*-105}=\frac{0-6\sqrt{35}}{-210} =-\frac{6\sqrt{35}}{-210} =-\frac{\sqrt{35}}{-35} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+6\sqrt{35}}{2*-105}=\frac{0+6\sqrt{35}}{-210} =\frac{6\sqrt{35}}{-210} =\frac{\sqrt{35}}{-35} $
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